12/ph/c2/6

Question 2.6: Three capacitors each of capacitance 9 pF are connected in series.

(a) What is the total capacitance of the combination?
(b) What is the potential difference across each capacitor if the combination is connected to a 120 V supply?
Answer :

(a) Capacitance of each of the three capacitors, C = 9 pF
Equivalent capacitance (C) of the combination of the capacitors is given by the relation,
Therefore, total capacitance of the combination is .
(b) Supply voltage, V = 100 V
Potential difference (V) across each capacitor is equal to one-third of the supply voltage.
Therefore, the potential difference across each capacitor is 40 V.




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